Sibley, Osceola County, Iowa, USA
Latitude: 43.3991, Longitude: -95.752
Birth
Matches 1 to 4 of 4
Last Name, Given Name(s) ![]() |
Birth ![]() |
Person ID | |
---|---|---|---|
1 | ![]() | IG4059 | |
2 | ![]() | 2 Nov 1907 | IG4149 |
3 | ![]() | 10 Apr 1895 | IL8306 |
4 | ![]() | 13 Mar 1921 | IL370 |
Death
Matches 1 to 3 of 3
Last Name, Given Name(s) ![]() |
Death ![]() |
Person ID | |
---|---|---|---|
1 | ![]() | 30 Nov 1926 | IL1714 |
2 | ![]() | 25 Jun 1994 | IL8806 |
3 | ![]() | 16 Oct 1980 | IS421 |